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3*5^2x=1875
We move all terms to the left:
3*5^2x-(1875)=0
Wy multiply elements
15x^2-1875=0
a = 15; b = 0; c = -1875;
Δ = b2-4ac
Δ = 02-4·15·(-1875)
Δ = 112500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112500}=\sqrt{22500*5}=\sqrt{22500}*\sqrt{5}=150\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150\sqrt{5}}{2*15}=\frac{0-150\sqrt{5}}{30} =-\frac{150\sqrt{5}}{30} =-5\sqrt{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150\sqrt{5}}{2*15}=\frac{0+150\sqrt{5}}{30} =\frac{150\sqrt{5}}{30} =5\sqrt{5} $
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